

A165714


Let the prime factorization of m be m = product p(m,k)^b(m,k), where p(m,j)<p(m,j+1) for all j, the p's are the distinct primes dividing m, and each b is a positive integer. Then a(n) = product_k {p(A165713(n), k)^b(n,k)}.


1



3, 2, 25, 7, 10, 2, 27, 121, 6, 13, 28, 2, 15, 6, 83521, 19, 50, 23, 63, 22, 6, 5, 104, 9, 14, 24389, 99, 31, 42, 2, 69343957, 34, 35, 6, 1444, 41, 39, 10, 88, 43, 30, 47, 45, 92, 6, 7, 80, 2809, 867, 26, 12, 59, 6655, 14, 513, 58, 62, 61, 132, 2, 21, 325, 90458382169, 34
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